Revise, Reflect, Refine
A crane lifts a mass m to the 10th floor of a building in a certain time. It then raises the same mass to the 20th floor of the same building in double the time. How much more energy and power are required? Assume that the height of all floors is equal.
Let the height of each floor = H, so:
Height to 10th floor = 10H.
Height to 20th floor = 20H.
Let the time to reach the 10th floor = t, so time to reach 20th floor = 2t.
Energy to lift to 10th floor: E₁ = mg(10H)
Energy to lift to 20th floor: E₂ = mg(20H) = 2 × mg(10H) = 2E₁
Extra energy required = E₂ − E₁ = 2E₁ − E₁ = E₁ = mg(10H).
The crane needs exactly as much MORE energy as it used for the first lift.
Power for 10th floor: P₁ = E₁/t = mg(10H)/t
Power for 20th floor: P₂ = E₂/(2t) = mg(20H)/(2t) = mg(10H)/t = P₁
The power required is the same in both cases.
Answer: The crane needs one additional amount of energy equal to mg(10H) — the same as the first lift. The power required is the same in both cases (P₁ = P₂ = mg·10H/t).
