Revise, Reflect, Refine
You want to design a new ionic compound where the total positive charge is 6+ and the total negative charge is 6−. Which of the following combinations gives the correct number of ions? (i) 2 Al³⁺ and 3 Cl⁻ (ii) 3 Mg²⁺ and 1 PO₄³⁻ (iii) 2 Fe³⁺ and 3 O²⁻ (iv) 3 Ca²⁺ and 2 SO₄²⁻
A balanced ionic compound requires total positive charge = total negative charge in magnitude.
(i) 2 Al³⁺ and 3 Cl⁻: Positive charge = 2 × 3 = 6+. Negative charge = 3 × 1 = 3−. 6+ ≠ 3−. Not balanced.
(ii) 3 Mg²⁺ and 1 PO₄³⁻: Positive charge = 3 × 2 = 6+. Negative charge = 1 × 3 = 3−. 6+ ≠ 3−. Not balanced.
(iii) 2 Fe³⁺ and 3 O²⁻: Positive charge = 2 × 3 = 6+. Negative charge = 3 × 2 = 6−. 6+ = 6−. Balanced. ✓
(iv) 3 Ca²⁺ and 2 SO₄²⁻: Positive charge = 3 × 2 = 6+. Negative charge = 2 × 2 = 4−. 6+ ≠ 4−. Not balanced.
Only option (iii) gives total positive charge = 6+ and total negative charge = 6−.
Answer: (iii) 2 Fe³⁺ and 3 O²⁻. Total positive charge = 2 × 3 = 6+; total negative charge = 3 × 2 = 6−. Charges balance.
