Revise, Reflect, Refine
The composition of the nuclei of three atomic species X, Y, and Z are given as follows. X: protons = 18, neutrons = 19. Y: protons = 17, neutrons = 18. Z: protons = 17, neutrons = 20. Explain the relation between the following: (i) Y and Z, (ii) Z and X.
Calculate the mass number (A = protons + neutrons) for each species:
X: A = 18 + 19 = 37
Y: A = 17 + 18 = 35
Z: A = 17 + 20 = 37
(i) Relation between Y and Z:
Y has 17 protons and Z has 17 protons — the same atomic number (same element, Chlorine).
But Y has mass number 35 and Z has mass number 37 — different mass numbers (different numbers of neutrons).
Y and Z are ISOTOPES — atoms of the same element with the same number of protons but different numbers of neutrons.
(ii) Relation between Z and X:
Z has 17 protons and X has 18 protons — different atomic numbers (different elements).
But Z has mass number 37 and X also has mass number 37 — the same mass number.
Z and X are ISOBARS — atoms of different elements that have the same mass number.
Answer: (i) Y and Z are isotopes (same proton number 17, different mass numbers 35 and 37). (ii) Z and X are isobars (same mass number 37, different proton numbers 17 and 18).
