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Class 12 Biology

Chapter 4 Solutions — Principles of Inheritance and Variation

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Solutions

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Step-by-step NCERT solutions for Principles of Inheritance and Variation (Chapter 4, CBSE Class 12 Biology) — every question and answer worked out in full, not just the final result. You can also read the Principles of Inheritance and Variation textbook chapter.

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What these solutions cover

All 16 questions in Principles of Inheritance and Variation are solved in the PDF. Here's what's inside, exercise by exercise:

Chapter-end Exercises

  1. Mention the advantages of selecting pea plant for experiment by Mendel.
  2. Differentiate between the following —
    • (a) Dominance and Recessive
    • (b) Homozygous and Heterozygous
    • (c) Monohybrid and Dihybrid.
  3. A diploid organism is heterozygous for 4 loci, how many types of gametes can be produced?
  4. Explain the Law of Dominance using a monohybrid cross.
  5. Define and design a test-cross.
  6. Using a Punnett Square, workout the distribution of phenotypic features in the first filial generation after a cross between a homozygous female and a heterozygous male for a single locus.
  7. When a cross is made between tall plant with yellow seeds (TtYy) and tall plant with green seed (Ttyy), what proportions of phenotype in the offspring could be expected to be
    • (a) tall and green.
    • (b) dwarf and green.
  8. Two heterozygous parents are crossed. If the two loci are linked what would be the distribution of phenotypic features in F₁ generation for a dihybrid cross?
  9. Briefly mention the contribution of T.H. Morgan in genetics.
  10. What is pedigree analysis? Suggest how such an analysis can be useful.
  11. How is sex determined in human beings?
  12. A child has blood group O. If the father has blood group A and mother has blood group B, work out the genotypes of the parents and the possible genotypes of the other offsprings.
  13. Explain the following terms with example
    • (a) Co-dominance
    • (b) Incomplete dominance
  14. What is point mutation? Give one example.
  15. Who had proposed the chromosomal theory of the inheritance?
  16. Mention any two autosomal genetic disorders with their symptoms.
Sample

Worked examples

3 questions from Principles of Inheritance and Variation, solved step by step.

Chapter-end Exercises

Mention the advantages of selecting pea plant for experiment by Mendel.

Mendel selected garden pea (Pisum sativum) for his hybridisation experiments due to several advantageous features:

1. Pea plants have many distinguishable contrasting characters (7 pairs of traits such as tall/dwarf, round/wrinkled seeds, yellow/green seeds, etc.) that are easy to observe and score.

2. They are naturally self-pollinating, which ensures true-breeding (homozygous) lines are easy to maintain.

3. Cross-pollination can be performed easily by hand, allowing controlled hybridisation experiments.

4. They have a short generation time and produce a large number of offspring, enabling statistically significant data.

5. Plants are easy and inexpensive to grow and maintain in large numbers.

6. Traits are distinct with no intermediate forms (discontinuous variation), making scoring unambiguous.

Answer: Pea plants have clearly contrasting traits, are naturally self-pollinating (allowing true-breeding lines), permit easy cross-pollination, have a short generation time, and produce large numbers of offspring — all of which made them ideal for Mendel's experiments.

Chapter-end Exercises

A diploid organism is heterozygous for 4 loci, how many types of gametes can be produced?

For a diploid organism heterozygous at a single locus (e.g., Aa), two types of gametes are produced: A and a.

For each additional heterozygous locus, the number of gamete types doubles (assuming independent assortment).

The formula is: Number of gamete types = 2ⁿ, where n = number of heterozygous loci.

Here, n = 4.

Number of gamete types = 2⁴ = 16.

Answer: 16 types of gametes (2⁴ = 16, where n = 4 heterozygous loci).

Chapter-end Exercises

Explain the Law of Dominance using a monohybrid cross.

Law of Dominance states that: (i) characters are controlled by discrete units called factors (genes); (ii) factors occur in pairs; (iii) in a pair of dissimilar factors, one member (dominant) dominates the other (recessive) and is expressed.

Illustration using a monohybrid cross (tall × dwarf pea):

Parents: Tall (TT) × Dwarf (tt)

Gametes from tall parent: T only

Gametes from dwarf parent: t only

F₁ generation: All progeny are Tt (genotype) → All plants are Tall (phenotype).

Here, only the dominant character (tallness, T) is expressed; the recessive character (dwarfness, t) is not seen, even though the t allele is present.

F₁ × F₁ (Tt × Tt):

Gametes: T and t (from each parent)

F₂ genotypes: 1 TT : 2 Tt : 1 tt

F₂ phenotypes: 3 Tall : 1 Dwarf (phenotypic ratio 3:1)

The dominant character (tallness) is expressed in both TT and Tt plants; the recessive character (dwarfness) is expressed only in tt plants. The Law of Dominance explains why only one parental character is seen in F₁ and why both appear in F₂ in a 3:1 ratio.

Answer: The Law of Dominance states that in a pair of contrasting alleles, the dominant allele masks the recessive. In a monohybrid cross (TT × tt), all F₁ are Tt and phenotypically tall (dominant). In F₂ (Tt × Tt), the phenotypic ratio is 3 Tall : 1 Dwarf, demonstrating that T dominates t.

All 16 questions in Principles of Inheritance and Variation are solved step by step in the Solutions PDF above.

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