Let Us Do — Common Multiples (p. 166)
Food is available at the end of a cobbled road. Robby, the rabbit, takes a jump of 4 each time. Deeku, the deer, takes a jump of 6 each time. They both start at 0. Will both Robby and Deeku reach the food? Who will reach first? How do you know? Explain your answer.
The cobbled road goes from 0 to 64 (food is at position 64).
Robby (jumps of 4) lands on: 4, 8, 12, 16, ..., 60, 64.
64 / 4 = 16 — YES, Robby reaches 64 in exactly 16 jumps.
Deeku (jumps of 6) lands on: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, ...
64 / 6 = 10 remainder 4 — NO, Deeku cannot reach 64 exactly.
64 is NOT a multiple of 6.
So only Robby the rabbit reaches the food. Deeku the deer never lands on 64.
Answer: Only Robby the rabbit reaches the food. 64 is a multiple of 4 (4 x 16 = 64), so Robby lands there in 16 jumps. 64 is not a multiple of 6 (64 / 6 = 10 r 4), so Deeku never lands on it.
