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Solutions

Overview

Step-by-step NCERT solutions for Quadrilaterals (Chapter 4, NCERT Class 8 Mathematics) — every question and answer worked out in full, not just the final result. You can also read the Quadrilaterals textbook chapter.

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What these solutions cover

All 19 questions in Quadrilaterals are solved in the PDF. Here's what's inside, exercise by exercise:

Rectangles and Squares

  1. Find all the other angles inside the following rectangles.
    • (i) Rectangle with vertices D(top-left), C(top-right), A(bottom-left), B(bottom-right). The diagonal AC makes an angle of 30° with the base AB at vertex A, i.e. ∠CAB = 30°.
    • (ii) Rectangle with vertices Q(top-left), R(top-right), P(bottom-left), S(bottom-right). The diagonals QS and RP meet at O, and the angle at O opening towards the top…
  2. Draw a quadrilateral whose diagonals have equal lengths of 8 cm that bisect each other, and intersect at an angle of
    • (i) 30°
    • (ii) 40°
    • (iii) 90°
    • (iv) 140°.
  3. Consider a circle with centre O. Line segments PL and AM are two perpendicular diameters of the circle. What is the figure APML? Reason and/or experiment to figure this out.
  4. We have seen how to get 90° using paper folding. Now, suppose we do not have any paper but two sticks of equal length, and a thread. How do we make an exact 90° using these?
  5. We saw that one of the properties of a rectangle is that its opposite sides are parallel. Can this be chosen as a definition of a rectangle? In other words, is every quadrilateral that has opposite sides parallel and equal, a rectangle?

More Quadrilaterals with Parallel Opposite Sides (Parallelograms and Rhombuses)

  1. Find the remaining angles in the following quadrilaterals.
    • (i) Parallelogram PEAR: ∠P = 40°.
    • (ii) Parallelogram SPQR: ∠P = 110°.
    • (iii) Rhombus XWVU: the diagonal at V makes 30° with each side (∠XVW = ∠XVU = 30°, so full ∠V = 60°).
    • (iv) Rhombus OIAE: the diagonal at E makes 20° with each side (∠OEI = 20°, so full ∠E = 40°).
  2. Using the diagonal properties, construct a parallelogram whose diagonals are of lengths 7 cm and 5 cm, and intersect at an angle of 140°.
  3. Using the diagonal properties, construct a rhombus whose diagonals are of lengths 4 cm and 5 cm.

Kite and Trapezium

  1. Find all the sides and the angles of the quadrilateral obtained by joining two equilateral triangles with sides 4 cm.
  2. Construct a kite whose diagonals are of lengths 6 cm and 8 cm.
  3. Find the remaining angles in the following trapeziums —
    • (i) A trapezium with bottom angles 135° and 105°.
    • (ii) An isosceles trapezium with one angle of 100°.
  4. Draw a Venn diagram showing the set of parallelograms, kites, rhombuses, rectangles, and squares. Then answer:
    • (i) What is the quadrilateral that is both a kite and a parallelogram?
    • (ii) Can there be a quadrilateral that is both a kite and a rectangle?
    • (iii) Is every kite a rhombus? If not, what is the correct relationship between these two types of quadrilaterals?
  5. If PAIR and RODS are two rectangles, find ∠IOD. (In rectangle PAIR: P(top-left), A(top-right), I(bottom-right), R(bottom-left); the left side PR = 5 cm. The vertex O of rectangle RODS lies on the side AI, and RO makes an angle of 30° with the base RI, i.e. ∠ORI = 30°. In rectangle RODS the vertices are R, O, D, S in order, with the side RS = 5 cm.)
  6. Construct a square with diagonal 6 cm without using a protractor.
  7. CASE is a square. The points U, V, W and X are the midpoints of the sides of the square. What type of quadrilateral is UVWX? Find this by using geometric reasoning, as well as by construction and measurement.
  8. If a quadrilateral has four equal sides and one angle of 90°, will it be a square? Find the answer using geometric reasoning as well as by construction and measurement.
  9. What type of a quadrilateral is one in which the opposite sides are equal? Justify your answer. Hint: Draw a diagonal and check for congruent triangles.
  10. Will the sum of the angles in a quadrilateral such as the following one (a non-convex/concave quadrilateral, where one vertex D lies inside triangle ABC) also be 360°? Find the answer using geometric reasoning as well as by constructing this figure and measuring.
  11. State whether the following statements are true or false. Justify your answers.
    • (i) A quadrilateral whose diagonals are equal and bisect each other must be a square.
    • (ii) A quadrilateral having three right angles must be a rectangle.
    • (iii) A quadrilateral whose diagonals bisect each other must be a parallelogram.
    • (iv) A quadrilateral whose diagonals are perpendicular to each other must be a…
Sample

Worked examples

3 questions from Quadrilaterals, solved step by step.

Rectangles and Squares

We saw that one of the properties of a rectangle is that its opposite sides are parallel. Can this be chosen as a definition of a rectangle? In other words, is every quadrilateral that has opposite sides parallel and equal, a rectangle?

This is a Try This problem. The question asks whether 'opposite sides parallel and equal' is sufficient to define a rectangle.

Answer: NO — this condition alone is not sufficient to define a rectangle.

A parallelogram has opposite sides parallel and equal by definition, but a parallelogram need NOT have right angles.

For example, a rhombus (not a square) has all sides equal (so opposite sides equal) and opposite sides parallel, but its angles are not 90°.

More generally, any non-rectangular parallelogram has opposite sides parallel and equal, yet is not a rectangle.

Therefore, 'opposite sides parallel and equal' describes a PARALLELOGRAM, which is a broader set than rectangles.

A rectangle requires the additional condition that all angles are 90° (or equivalently, that the diagonals are equal).

Answer: No. A quadrilateral with opposite sides parallel and equal is a parallelogram, which need not be a rectangle. An additional condition (all angles = 90°, or diagonals equal) is needed to guarantee a rectangle.

Kite and Trapezium

Find all the sides and the angles of the quadrilateral obtained by joining two equilateral triangles with sides 4 cm.

Take two equilateral triangles PQR and PQS, each with sides 4 cm, joined along the common side PQ.

The resulting quadrilateral has vertices R, Q, S, P (going around).

Sides:

All four sides of the quadrilateral = the sides of the equilateral triangles = 4 cm each.

So it is a rhombus with all sides = 4 cm.

Angles:

Each interior angle of an equilateral triangle = 60°.

At vertex R (or S): only one triangle contributes ⇒ angle R = angle S = 60°.

At vertex P (or Q): two triangles meet, each contributing 60° on the same side of PQ.

angle at P = angle RPQ + angle SPQ = 60° + 60° = 120°.

angle at Q = angle RQP + angle SQP = 60° + 60° = 120°.

Check: 60° + 120° + 60° + 120° = 360° ✓

The quadrilateral RPSQ (or RQSP) is a rhombus with:

All sides = 4 cm, angles at R and S = 60°, angles at P and Q = 120°.

Answer: The quadrilateral is a rhombus with all sides = 4 cm; angles at R and S = 60°, angles at P and Q = 120°.

Kite and Trapezium

If PAIR and RODS are two rectangles, find ∠IOD. (In rectangle PAIR: P(top-left), A(top-right), I(bottom-right), R(bottom-left); the left side PR = 5 cm. The vertex O of rectangle RODS lies on the side AI, and RO makes an angle of 30° with the base RI, i.e. ∠ORI = 30°. In rectangle RODS the vertices are R, O, D, S in order, with the side RS = 5 cm.)

Rectangle PAIR: P(top-left), A(top-right), I(bottom-right), R(bottom-left).

The vertex O of rectangle RODS sits on the side AI of PAIR, and ∠ORI = 30° is given (angle at R between RO and the base RI).

Step 1: Find ∠ROI in triangle ROI.

Since PAIR is a rectangle, its side AI is perpendicular to its side RI, so ∠OIR = 90° (O lies on AI, directly above I).

In right triangle ROI: ∠ROI = 90° − ∠ORI = 90° − 30° = 60°.

Step 2: Use the right angle of rectangle RODS at O.

In rectangle RODS the vertices go R → O → D → S, so the sides RO and OD meet at O at a right angle: ∠ROD = 90°.

Step 3: Find ∠IOD.

The ray OI lies inside ∠ROD (O–I is between O–R and O–D), so

∠IOD = ∠ROD − ∠ROI = 90° − 60° = 30°.

Therefore ∠IOD = 30°.

Answer: ∠IOD = 30°. (Since AI ⊥ RI in rectangle PAIR, ∠ROI = 90° − 30° = 60°; since ∠ROD = 90° in rectangle RODS, ∠IOD = 90° − 60° = 30°.)

All 19 questions in Quadrilaterals are solved step by step in the Solutions PDF above.

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